Answer:
The statement, one fifth of the square of a number is written as
![\frac{1}{5} {x}^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B5%7D%20%20%7Bx%7D%5E%7B2%7D%20)
Hope this helps you
Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
Answer:
[-1,5]
Step-by-step explanation:
all reals between -1 and 5
3x+3=90
subtract 3 from both sides
3x=87
divide both sides by 3
x=29
To find IJ, plug in the x value
x+8+x-9
29+8+29-9
57=IJ