The answer is rounded to the nearest tenth.
Which explains whether or not the function represents a direct variation? This function represents a direct variation because it
passes through the origin and has a constant rate of change of $5 per hour. This function represents a direct variation because it has a positive, constant rate of change of $10 per hour. O This function does not represent a direct variation because it does not represent the cost for 1 hour. O This function does not represent a direct variation because the function rule for the cost is to add $10, not multiply by a constant. Which explains whether or not the function represents a direct variation ? This function represents a direct variation because it passes through the origin and has a constant rate of change of $ 5 per hour . This function represents a direct variation because it has a positive , constant rate of change of $ 10 per hour . O This function does not represent a direct variation because it does not represent the cost for 1 hour . O This function does not represent a direct variation because the function rule for the cost is to add $ 10 , not multiply by a constant .
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Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that . Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that . In this equality we can perform a right multiplication by
and obtain
. Then, in the obtained equality we perform a left multiplication by P and get
. If we write
and
we have
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and . So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.