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andre [41]
3 years ago
8

A rectangular conductor with a cross sectional area of 1.04 square millimeters (mm) ^2 has a resistance of 0.075 ohms. What woul

d be its resistance, if it's cross sectional area were 2.08mm^2​
Engineering
1 answer:
kogti [31]3 years ago
4 0

Answer:

0.0375 ohms

Explanation:

The resistance of a material is the product of the resistivity of the material by the length of the material divided by its cross-section area.

Mathematically,

resistance= resistivity × length/area

In this case the resistivity of the material is the same, and the length is the same thus, assume a length of 1 unit, the cross-section area is the one changing

In applying the formula,

resistivity is r and length is l=1 unit, find the resistivity the material as;

resistance= resistivity * length /area

0.075=r*1/1.04

0.075=r*0.9615

0.075/0.9615 =r

r=0.078

use the r=0.078 , a length of 1 unit (assumed), and area of 2.08 mm² to find the new resistance

Resistance= resistivity * length /area

Resistance = 0.078*1/2.08

Resistance= 0.078 * 0.4807 = 0.0375 ohms

Point to note here is that the greater the cross-section area, the less the resistance.

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ehidna [41]

Answer:

Change in length = 0.1257 mm

Change in diameter= -0.03771mm

Explanation:

Given

Diameter, d = 15 mm

Length of rod, L = 200mm

F = Force= 300N

d = 0.015m

Ep=2.70 GPa, np=0.4.

First, we have to calculate the normal stress using

σ = F/A where F = Force acting on the Cross-sectional area

A = Area

Area is calculated as πd²/4 where d = 0.015m

A = 22/7 * 0.015²/4

A = 0.000176785714285m²

A = 1.768E-4m²

So, stress. σ = 300N/1.768E-4m²

σ = 1696832.579185520Pa

σ = 1.697MPa

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E(long) = 1.697E-3/2.70

E(long) = 0.0006285

At this point, we fan now calculate the change in length of the element;

∆L = E(long) * L

∆L = 0.0006285 * 200mm

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Calculating E(lat)

E(lat) = -np * E(long)

E(lat) = -4 * 0.0006285

E(lat) = -0.002514

At this point, we can now calculate the change in diameter of the element;

∆D = E(lat) * D

∆L = -0.002514 * 15mm

∆L = -0.03771mm

8 0
3 years ago
Python:
stira [4]

Answer:

# Python Program to Print  

# all subsets of given size of a set  

 

import itertools  

 

def findsubsets(s, n):  

   return list(itertools.combinations(s, n))  

 

# Driver Code  

s = {1, 2, 3}  

n = 2

 

print(findsubsets(s, n))

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# Python Program to Print  

# all subsets of given size of a set  

 

import itertools  

# def findsubsets(s, n):  

def findsubsets(s, n):  

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# Driver Code  

s = {1, 2, 3, 4}  

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print(findsubsets(s, n))

-------------------------------------------------------------

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# all subsets of given size of a set  

 

import itertools  

from itertools import combinations, chain  

 

def findsubsets(s, n):  

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# Driver Code  

s = {1, 2, 3}  

n = 2

 

print(findsubsets(s, n))

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