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Solnce55 [7]
2 years ago
15

A 50 meter chain with uniform density and a mass of 40 kilograms is hanging from the roof of a building under construction. How

much work (in Nm) is required to pull the chain up?
Mathematics
2 answers:
Brums [2.3K]2 years ago
8 0

Answer:

19,600 Nm

Step-by-step explanation:

WD = mgh

= 40 × 9.8 × 50

= 19600 Nm

sertanlavr [38]2 years ago
5 0

Answer:

W = 19600 N m

Step-by-step explanation:

W = force * distance

The force is the weight times gravity since it is hanging down

W = 40 kg* 9.8 m/s^2 * 50m

    19600 kg m^2/s^2

A newton is  kg m/ s^2

W = 19600 N m

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How to find increase percent from 44 to 48
lesantik [10]
9.09% increase.

First find the difference between the two numbers.

(4)

then, divide the result by the original amount...

4÷ 44

then multiply by 100

9.09 and that is to the nearest 10th otherwise your answer 9% increase from 44 to 48.
3 0
3 years ago
Evaluate f(x) = sqrt(5x + 4) for x = 12
Nezavi [6.7K]

Answer is 8

Work Shown:

f(x) = sqrt(5*x + 4)

f(12) = sqrt(5*12 + 4) ... replace every x with 12

f(12) = sqrt(60 + 4)

f(12) = sqrt( 64 )

f(12) = 8

8 0
3 years ago
Why does the table say "inches of rain"?
elena-s [515]

By what I can tell, that is telling you what the measurement of rain was per month.  For example, August had 10.  That means that in the month of August there was 10 inches of rain.

8 0
2 years ago
Please help me with this:(
dolphi86 [110]

Answer:

Y = 32.7°

Step-by-step explanation:

We will apply the Cosine law in the given triangle XYZ,

x = 90 ft

y = 55 ft

z = 50 ft

We have to find the measure of angle Y.

y² = x² + z² - 2xzCosY

(55)² = (90)² + (50)² - 2(90)(50)cosY

3025 = 8100 + 2500 - 9000.cosY

9000.cosY = 10600 - 3025

cosY = \frac{7575}{9000}

        = 0.84167

Y = \text{cos}^{-1}(0.84167)

Y = 32.68 ≈ 32.7°

Therefore, measure of angle Y = 32.7°

5 0
3 years ago
Write the value of 4 in 305,444
BigorU [14]
Divide 305444 by 4

305444 / 4
76361

so
76361 times 4 is equal to 76361
3 0
3 years ago
Read 2 more answers
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