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sp2606 [1]
1 year ago
6

Factorize x^4 + 2x^3 - 11x^2 - 12x + 36 I need the steps.Please i need this for today.

Mathematics
1 answer:
Yuliya22 [10]1 year ago
6 0

x^4 +2x^3 -11x^2-12x+36\\ \\=x^4-2x^3+4x^3-8x^2-3x^2 +6x-18x+36\\\\=x^3(x-2)  +4x^2(x-2)  -3x(x-2)   -18(x-2)\\\\=(x-2)(x^3 +4x^2 -3x -18)\\\\=(x-2)(x^3+3x^2+x^2+3x-6x-18)\\\\=(x-2)\textbf{[}x^2(x+3)+x(x+3)-6(x+3)\textbf{]}\\\\=(x-2)(x+3)(x^2 +x -6)\\\\=(x-2)(x+3)(x^2 +3x -2x-6)\\\\=(x-2)(x+3)\textbf{[}x(x+3) -2(x+3)\textbf{]}\\\\=(x-2)(x-2)(x+3)(x+3)\\\\=(x-2)^2(x+3)^2

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\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
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We'll take log of each side.
Log of what base tho?

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\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
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