Answer:
We have (x 2
−2x) 10 =x 20 (1− x
2 ) 10
and since x 20 multiplies every term in the expansion of (1− x
2 ) 10 we have in this expansion to seek the coefficient of the term which contains
x 4
1
Hence the required coefficient
10
C 4 (−2) 4
= 1.2.3.4 10.9.8.7×16=3360
<h2>
Please mark me as brainliest</h2>
Step-by-step explanation:
x= undefined
y= 0
____________
8/5 = 1 3/5
(5 x 1 = 5 + 3 = 8, to get 8/5)
13/12 = 1 1/12 (12 x 1 = 12 + 1 = 13, to get 13/12)
Hope this helped! :D
Answer:
D
Step-by-step explanation:
The answer is d
Multiplicity is hoa many times it repeats
example
if you have roots, r1 multiplicity 2 and r2 multiliicty 3 the factors are
f(x)=(x-r1)^2(x-r2)^3
so
multiplicty 2 at x=4
multilicty 1 at x=-2
(x-4)^2(x-(-2))^1=
(x-4)^2(x+2))
expand
x^3-6x^2+32
remember
for roots, r1 and r2
(x-r1)(x-r2)
the roots don't change if you multiply whold thing by a unless a=0
so
the yint is where x=0
so the yint now is 32
32 times what=-9.6?
divide both sides by 32
what=-0.3
the polynomial is
p(x)=-0.3(x-4)²(x+2)
expanded is
p(x)=-0.3x³+1.8x²-9.6