Answer:
x = -4y
<em>Hope that helps! :)</em>
<em>-Aphrodite</em>
Step-by-step explanation:
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
I believe the answer is a 20% increase because 12-10 equals 2. there is a 2 record difference so 2 out of 10 is 1/5 of the whole, but you have to convert the numbers and 1/5 of the whole of 100 is 20. sorry if that didn’t make much sense
I did x - 10 =290
+10 +10
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x = 300 so they took $1.00 a day
9+3 =12
12/4 = 3
(3)2-4(3)-3
6-12-3
-9 is the answer