Answer:
3x²+6x+10 is your answer
Step-by-step explanation:
(x^2+6x-5)+(2x^2+15)
open bracket
x²+6x-5+2x²+15
add or subtract common
3x²+6x+10
-- A 'multiple' (lcm) is always at least as big as the biggest original number.
The lcm of 2, 8, 64, and 512 is 512 .
-- A 'factor' (gcf) is never bigger than the smallest original number.
The gcf of 2, 8, 64, and 512 is 2 .
Of the 100 students, 37 take only Spanish. Subtracting 37 from 100 gives us 63 students who are taking either both Spanish and Chinese or only Chinese.
So, there are 63 students who are taking Chinese (just Chinese or both Chinese and Spanish).
Since the number of students taking Chinese is 8 more than the number of students taking Spanish, 63 - 8 + 55 students taking Spanish (just Spanish or both Spanish and Chinese).
Of these 55 students, 37 are only taking Spanish, therefore, 55 - 37 = 18 students who are taking both languages.
I guess a whole lot shorter way of looking at this is: for there to be 8 more students taking Chinese than Spanish, there must be 8 more students who are taking only Chinese than who are taking only Spanish: 37 + 8 = 45. Since 37 are taking only Spanish and 45 are taking only Chinese, 100 - (37 + 45) = 18 students who are taking both languages.
If the original price =$50
If we take $20 off, we have: $50-20 =$30
Next, taking 25% off of $30, we have:
Final Price = (100%-25%) of $30
=0.75 x 30
Final Price Final 0Price=$22.5
9
If we take $20 off, we have: $90-20 =$70
Next, taking 25% off of $70, we have:
Final Price = (100%-25%) of $70
=0.75 x 70
Final Price =$52.50
3^(1/2)+(1/2)=3^1=3
If you take 3 for 1/2 of the time and the other 3 for 1/2 of the time you get 3 one time, that is 3.