3 years ago

When you find 420% of 85, what are you looking for? Are you looking for the percent, the part, the whole or a ratio

Mathematics

1 answer:

maw [93]3 years ago

6 0

Answer:

percent

Step-by-step explanation:

it has a percent sign

Please mark me brainliest

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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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3 years ago

Use the formula A = h(b1 + b2).<br> What is the area of the trapezoid?<br> square units

deff fn [24]

Only use h=trapezoid's height.

b=base

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lozanna [386]

There are 0 x intercepts for this equation.

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3 years ago

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gregori [183]

Answer:

no solutions

Step-by-step explanation:

I believe there are no solutions for these 2 equations.

Hope this helps!

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Sergeeva-Olga [200]

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