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2 years ago

What is 6.2 x 10^9 expressed as a decimal?

Mathematics

1 answer:

Anestetic [448]2 years ago

3 0

Answer:6,200,000,000

Step-by-step explanation: Since the exponent get smaller the number get bigger therefore don't get confused on whether it is a decimal because all whole numbers have a imaginary decimal.

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942 ÷ 7 = ? A. 134 R4 B. 136 C. 134 R2 D. 133 R1

zimovet [89]

Answer:

Step-by-step explanation:

134

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2 years ago

Read 2 more answers

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omeli [17]

cant understand your language can you translate in English

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2 years ago

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bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

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2 years ago

HELP NOW IS THIS CORRECT

Arisa [49]

Yes this question is correct

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2 years ago

4 is added to the data set 22, 25, 31, 33, 24. Answer true or false for the following statements.

Vedmedyk [2.9K]

Answer:

The range and mean will increase - False

(because only range will increase, mean will decrease)

The mean and median will decrease - True

The mean will decrease but the median will stay the same - False

(Both of mean and median will decrease)

An outlier is more likely to change the median than the mean - False

(An outlier is more likely to change the mean than the median)

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3 years ago