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Sauron [17]
3 years ago
10

A rope is tied to the bottom of a hot air balloon ad shown below The rope makes an angle of 35 with the ground and is 75 ft long

. How far is the bottom of the balloon from the ground to the nearest foot .
Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

The answer to your question is 43 ft

Step-by-step explanation:

Data

angle = Ф = 35°

length = 75 ft

height = ?

Process

To solve this problem, use trigonometric functions. The trigonometric function that relates the Opposite side (height) and the hypotenuse (length) is sine.

               sin Ф = Height / length

-Solve for height

                height = length x sin Ф

-Substitution

                height = 75 x sin 35

-Simplification

                height = 75 x 0.574

-Result

                 height = 43 ft

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Step-by-step explanation:

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Step-by-step explanation:

꧁§༺⚔A real friend is one who walks in when the rest of the world walks out.” ⚔༻§꧂

8 0
2 years ago
Give another name plane L
horrorfan [7]

Answer:

Any one of these three works:

plane MOU

plane MNU

plane NOU

Step-by-step explanation:

A plane can be named by a single letter, such as L in this problem, or by any three non-collinear points that lie on the plane. Non-collinear points are points that do not all lie in a single line.

Points M, N, O, and U lie on plane L, so you can choose any 3 of the 4 points to name the plane with, but make sure all 3 points are non-collinear.

To name plane L with points, you cannot use points MNO together since they are collinear, but you can name it using point U plus any two of the points M, N, and O.

plane L can be named

plane MOU

plane MNU

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6 0
3 years ago
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
3 years ago
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viva [34]
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Then, you can add 30 to both sides and add 5x to both sides to get 0=-23x

Finally, you divide both sides by -23 to get 0=x
6 0
3 years ago
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