Answer:
- 40, - 50, - 60
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence.
- 20 - (- 10) = - 20 + 10 = - 10
- 30 - (- 20) = - 30 + 20 = - 10
Thus the difference d = - 10
To obtain a term in the sequence subtract 10 from the previous term
- 30 - 10 = - 40
- 40 - 10 = - 50
- 50 - 10 = - 60
The next 3 terms are - 40, - 50, - 60
11/15 + 7 ⇒ rational ⇒ the sum of two rationals is always rational
√14+13 ⇒ irrational ⇒ the sum of a rational and an irrational is always irrational
30×√6 ⇒ irrational ⇒ the product of a nonzero rational and an irrational is always irrational
11/12 × 7/15 ⇒ rational ⇒ the product of two rationals is always rational
Answer in the attachment.
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