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kupik [55]
3 years ago
11

In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

5

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1  5  5  7  9 ← data in ascending order

       ↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1  5

 ↑ lower quartile = \frac{1+5}{2} = 3

The upper quartile is the middle value of the data to the right of the median.

7  9

 ↑ upper quartile = \frac{7+9}{2} = 8

Thus

interquartile range = 8 - 3 = 5

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A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati
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Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
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3 years ago
5. Given the linear table below, what is the rate of change? *
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Sandra's scores on the first 4 tests were 87%, 92%, 76%,and 89%. What is the minimum score she needs to make on the fifth test s
sergejj [24]

Answer:

Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

Step-by-step explanation:

Given:

First 4 test scores = 87%, 92%, 76%,89%

Average targeted = 80%

We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.

Solution:

Let the minimum score she needs to make in fifth test be 'x'.

Total number of test = 5

Now we know that;

Average is equal to sum of all the scores in the test divided by number of test.

framing in equation form we get;

\frac{87+92+76+89+x}{5}=80

Multiplying both side by 5 we get;

\frac{344+x}{5}\times 5=80\times 5\\\\344+x=400

Subtracting both side by 344 we get;

344+x-344=400-344\\\\x=56\%

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

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3 years ago
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Answer:

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