In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Mathematics

1 answer:

Marizza181 [45]3 years ago

3 0

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

You might be interested in

If I needed to write in this format (A U B) how would i write it

MAXImum [283]

Answer:

n(AUB)=n(A)+n(B)–n(AnB)

n(AUB)=n⁰(A)+n⁰(B)+n(AnB)

Step-by-step explanation:

This is the formula i have learned. Hope this will help u. U can use them according the question type.

7 0

3 years ago

Which of the following describes a ratio of actual events to the number of trials in an experiment? Select all that apply. HELP

aleksklad [387]

Experiental probability is the correct choice because you will have actual data from an experiment that you are using to create the ratio of outcomes to attempts. This is the scientific and mathematical name for a tested ratio. Theoretical probability, on the other hand, is what you would expect to happen if you were to perform the test.

5 0

3 years ago

A die is rolled one thousand times. The percentage of aces should be around ____ or so. the first step iin computing this proble

Katyanochek1 [597]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$Box \ average =\frac{1}{6} \\\\SD = \frac{1}{6} \times \frac{5}{6} = \frac{5}{36} \approx 0.373\\\\Expected \ value= 1000 \times \frac{1}{6} \approx 166.7\\\\SE = 1000 \times 0.373 \approx 11.8\\\\$