Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.
That is;
P(x<0.496) and P(x>0.504) are not acceptable.
Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707
Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099
Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
The answer is: -2 because as x increases by 1 y decreases by -2
Answer:
Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Step-by-step explanation:
Given:
First 4 test scores = 87%, 92%, 76%,89%
Average targeted = 80%
We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.
Solution:
Let the minimum score she needs to make in fifth test be 'x'.
Total number of test = 5
Now we know that;
Average is equal to sum of all the scores in the test divided by number of test.
framing in equation form we get;

Multiplying both side by 5 we get;

Subtracting both side by 344 we get;

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Answer:
So first you have to do 12-2 since it's in parenthesis. It is 10. 5+4 is 9, and 9 times 10 is 90. 3 squared is 9, then you divide 90 by 9. The answer is 10.
Answer:
if I'm solving for x, then its 2
(I think)