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sineoko [7]
3 years ago
6

HELP WILL MARK BRAINLEST no files nd no pictures

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

<h3>6xsquared +9x + 12</h3>

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A recreation center ordered a total of 15 try schools and bicycles from a sporting good store. The number of wheels for all tric
Juli2301 [7.4K]

Answer: The linear system of equations that models this scenario are

T + B = 15

3T + 2B = 38

Step-by-step explanation:

Let T represent the number of tricycles.

Let B represents the number of bicycles ordered.

The recreation center ordered a total of 15 tricycles and bicycles from a sporting good store. It is expressed as

T + B = 15

A tricycle has three wheels. A bicycle has 2 wheels. The number of wheels for all tricycles and bicycles total 38. The expression would be

3T + 2B = 38

6 0
3 years ago
Solve question 3 for <br> 41 points
Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: ln(\frac{\sqrt{e} }{y^3} ).

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)

Also, we can write square roots as powers of one-half, so √e = e^{1/2}. There's another log property that: ln(a^b)=b*ln(a). We can apply that here for both the √e and the y³:

ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)

Finally, note that ln(e) is just 1, so we have:

\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}

The answer is thus (2).

<em>~ an aesthetics lover</em>

7 0
3 years ago
Find the number of distinguishable permutations of the letters ZEBRA​
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Step-by-step Answer:

Since there are no repetitions in the five letters of the word ZEBRA, the number of permutations is 5! = 120 = 5*4*3*2*1.

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3 years ago
9.32 decreased by seven thousandths.
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9.32-7000=-6990.68 is your answer

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