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Advocard [28]
4 years ago
7

Multiple similary transformations are performed on a triangle. Which elements must be presented?

Mathematics
1 answer:
solmaris [256]4 years ago
4 0

Answer:

d. overal size

Step-by-step explanation:

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calculate the distance between each given pair of points round your answer to the nearest tenth if necessary (3,1) and (6,5)
AnnZ [28]
The distance between (3, 1) and (6, 5) is 5.

D=√(x₂-x₁)²+(y₂-y₁)²
D=√(6-3)²+(5-1)²
D=√3²+4²
D=√9+16
D=√25
D=5
3 0
4 years ago
Whats a multiplication problem with a product of 5 to the 13th power
fredd [130]
5 to the 7th power times 5 to the 6th power
8 0
3 years ago
Tyler had $65.40 in his checking account. Then he wrote checks on the account for $20.38, $11.48, and $19.50. What is the balanc
andrew-mc [135]

money going out (20.38+11.48+19.50) =51.36

balance - out = new balance

65.40-51.36 =

14.04

new balance =  14.04

4 0
4 years ago
1. If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?
Ad libitum [116K]
A) If 9 students sharpen 18 pencils in 2 minutes,Then if the time is halved, it will take twice as many men to sharpen 18 pencils.Hence it will take 18 students to sharpen 18 pencils in one minute B) y & 1/x. Then y = K/x where K is our constant of proportionality.Then K = yx. When x = -64 and y = -16 then K = -64 * -16 = 1024. Option DC) When x = 3 y = 8. So for an inverse variation K as calculated from B = 3 * 8 = 24.Then when K = 24 and y = 6; we have 24 = 6x. Hence x = 4. Option A
6 0
3 years ago
$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent
photoshop1234 [79]

\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

7 0
3 years ago
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