The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
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The equation between the number of days remaining and number of hours is given as y= -5x+50.
<h3>How to illustrate the equation?</h3>
Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
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Answer:
y=2x+14
Step-by-step explanation:
y=mx+b
hope its right
X+y=44
x=5/6y
x+y=44
5/6y+y=44
11/6y=44
11y=264
y=24
x=5/6y=(5/6)*24=20
Answers: numbers are 20, 24
Answer:
equation: 320+x=360, answer: 40
Step-by-step explanation:
add 100,200 and 100 to get 320
360-320=40
x=40
