Answer:
Yes, the normal curve can be used as an approximation to the binomial probability.
Step-by-step explanation:
Let <em>X</em> = number of students that pass their college placement exam.
The probability that a given student will pass their college placement exam is, P (X) = <em>p</em> = 0.53.
A random sample of <em>n</em> = 127 students is selected.
The random variable <em>X</em> follows a Binomial distribution.
But the sample size is too large.
A Normal approximation to Binomial can be used to approximate the distribution of proportion <em>p</em>.
The conditions to be satisfied are:
- <em>np</em> ≥ 10
- <em>n</em>(1-<em>p</em>) ≥ 10
Check whether the conditions are satisfied as follows:
Both he conditions are satisfied.
Thus, a normal curve can be used as an approximation to the binomial probability.
You would move you positive 3 to the left side so (y) is by itself. So you would have 3x-8=y. Then substitute X=5. So 3(5)-8=y. 15-8=y. 7=y
The probability that the person uses exactly one of the facilities = 95/130 .
<h3>What is Probability ?</h3>
Probability is the branch of Mathematics which helps to determine the likeliness of an event to happen.
The data is given and the probability that the person uses exactly one of the facilities is asked
73 people use the gym. P(G)
62 people use the swimming pool. P (S)
58 people use the track. P (T)
22 people use the gym and the pool. P (G ∩ P)
29 people use the pool and the track. P (P ∩ T)
25 people use the gym and the track. P (G ∩ T)
11 people use all three facilities. P (P∩G∩T)
P (PUGUT) = P(G) + P (S) + P (T) - P (G ∩ P) - P (P ∩ T) - P (G ∩ T) - 2 P (P∩G∩T)
73 + 62 + 58 -22-29-25 -11-11 = 95
The probability that the person uses exactly one of the facilities = 95/130 .
To know more about Probability
brainly.com/question/11234923
#SPJ1
9514 1404 393
Answer:
103
Step-by-step explanation:
For 1200 eggs, the caterer needs ...
(1200 eggs)/(12 eggs/carton) = 100 cartons
of unbroken eggs.
The rate of broken eggs is 1 in 3×12 = 1 in 36, so the caterer must buy 36 eggs for each 35 unbroken eggs delivered.
Then the number of cartons that must be purchased is ...
(100 cartons)(36/35) = 102 6/7 cartons
The caterer should buy 103 cartons of eggs.
The answer should be
-7(2a-7)