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Lunna [17]
3 years ago
14

An electric stove marked 1700 plus sales tax at 13%. Find the purchase price of the given object.​

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

1921

Step-by-step explanation:

1700 * (1 + 0.13) = 1921

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WILL MARK BRAINLIEST
il63 [147K]

Answer:

1) c 2)c 3)b

Step-by-step explanation:

8 0
4 years ago
A small theater with 200 seats sells two kinds of tickets for a performance. Premium tickets sell for $20 each and Standard tick
KATRIN_1 [288]
P + s = 200......p = 200 - s
20p + 15s = 3400

20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold

p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
7 0
4 years ago
Point B, located at (-5, -8), is rotated 360°. What are the coordinates of point B?
Natalka [10]
(-5,-8)
The coordinates are still the same because a rotation of 360° is a complete circle, therefore the points remain in the same spot.
4 0
3 years ago
Read 2 more answers
What is the distance between two points with coordinates at (8, 40) and (20, 5)?
Alchen [17]

Answer:

37 units

Step-by-step explanation:

The two points form a right triangle so

a²+b²=c² so

(8-20)²(x values)+(40-5)²(y values)=c² (distance) so

12²+35²=c² so

144+1225=c²

1369=c²

c=37 units

7 0
3 years ago
Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted
inessss [21]

I suppose the integral could be

\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx

In that case, since -\frac1x\to0 as x\to\infty, we know e^{-1/x}\to1. We also have \left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0, so the integral is approach +1 from below. This tells us that, by comparison,

\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}

and the latter integral is convergent, so this integral must converge.

To find its value, let u=-\frac1x, so that \mathrm du=\frac{\mathrm dx}{x^2}. Then the integral is equal to

\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}

4 0
4 years ago
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