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Stella [2.4K]
3 years ago
12

Priscilla decides to order a delivery from the local sandwich shop. Her order comes to $12.74 and there is a $2.30 delivery char

ge. When the food is delivered, Priscilla adds on to her receipt a charge of 15% of her total, not including the delivery charge, as a tip for the driver. When Priscilla goes to check her debits on her online bank statement, what amount should she expect as her total debit?
Mathematics
2 answers:
siniylev [52]3 years ago
4 0

Answer:  $16.95

Step-by-step explanation:

Given: The cost of order of food =  $12.74

Delivery charge = $2.30

Then, the total cost of order =\$12.74+\$2.30=\$15.04

Since, when  the food is delivered, Priscilla adds on to her receipt a charge of 15% of her total, not including the delivery charge, as a tip for the driver.

Then the total amount should she expect as her total debit = \$15.04+0.15\times\$12.74=\$16.951\approx\$16.95

Hence, the total amount should she expect as her total debit \$16.95

tatyana61 [14]3 years ago
3 0
If $2.30 is in the 12.74 then her amount is $14.61.
If it is not included, her amount is $17.30.
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Makovka662 [10]
The answer, in short, is that the short leg equals 15 mm, the long leg equals 20 mm, and the hypotenuse equals 25mm. but if you'd like to see how I solved it, here are the steps.
-----------------------------
The Pythagorean theorem (also known as Pythagoras's Theorem) can be used to solve this. This theorem states that one leg or a right triangle squared plus the other side of that same triangle squared equals the hypotenuse of that triangle squared. To put it in equation form, L² + L² = H².

Let's call the longer leg B, the shorter leg A, and the hypotenuse H.
From the question, we know that A = B - 5, and H = B + 5. 

So if we put those values into an equation, we have (B - 5)² + B² = (B + 5)²

Now, to solve. Let's square the two terms in parentheses first:
(B² - 5B - 5B + 25) + B² = B² + 5B + 5B + 25

Now combine like terms:
2B² -10B + 25 = B² + 10B + 25

And now we simplify. Subtract 25 from each side:
2B² - 10B = B² + 10B

Subtract B² from each side:
B² - 10B = 10B

Add 10B to each side:
B² = 20B

And finally, divide each side by B:
B = 20

So that's the length of B. Now to find out A and H.
A = B - 5, so A = 15.
H = B + 5, so H = 25.

And your final answer is A = 15mm, B = 20mm, and H = 25mm
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3 years ago
2(3x+1)≤20 and 4(x−1)<2.
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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

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Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

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Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

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Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

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