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Stella [2.4K]
3 years ago
12

Priscilla decides to order a delivery from the local sandwich shop. Her order comes to $12.74 and there is a $2.30 delivery char

ge. When the food is delivered, Priscilla adds on to her receipt a charge of 15% of her total, not including the delivery charge, as a tip for the driver. When Priscilla goes to check her debits on her online bank statement, what amount should she expect as her total debit?
Mathematics
2 answers:
siniylev [52]3 years ago
4 0

Answer:  $16.95

Step-by-step explanation:

Given: The cost of order of food =  $12.74

Delivery charge = $2.30

Then, the total cost of order =\$12.74+\$2.30=\$15.04

Since, when  the food is delivered, Priscilla adds on to her receipt a charge of 15% of her total, not including the delivery charge, as a tip for the driver.

Then the total amount should she expect as her total debit = \$15.04+0.15\times\$12.74=\$16.951\approx\$16.95

Hence, the total amount should she expect as her total debit \$16.95

tatyana61 [14]3 years ago
3 0
If $2.30 is in the 12.74 then her amount is $14.61.
If it is not included, her amount is $17.30.
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find the area and perimeter of a rectangle with a width of 2 1/3inch and a length of 5 2/5inches. show your work please.
aleksandrvk [35]
Area: If you multiply 2 1/3 by 5 2/5, you get an answer of about: 12.6, which means the area is about: 12.6in. squared.
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Note: If you aren't allowed to use a calculator on this test, you should probably multiply the numbers yourself so you get show the work and get the answer in a fraction, which is probably what they want. If you are allowed to use calculators, all the information you need is right here.
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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
The official run time of a movie is 140 minutes.Your friend who has seen the movie says its about 2.3 hours
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A.
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B.
2.(3) > 2.3 ;
your friend underestimate the length of the movie ;
3 0
3 years ago
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