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Volgvan
3 years ago
8

Deon rented a truck for one day there was a base fee of $19.99 and there was an additional charge of 98 cents for each mile driv

en deon had to pay $216.97 when he returned the truck for how many miles did he drive the truck
Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

Deon drove the truck 201 miles.

Step-by-step explanation:

Base Fee + (.98* Number of miles)= Cost

19.99 + .98x = 216.97

Subtract 19.99 from both sides.

.98x = 196.98

Divide both sides by .98

x = 201

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Answer:

7

Step-by-step explanation:

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4 0
2 years ago
Find three consecutive even integers if three times the first integer is two times<br> the third
lara31 [8.8K]

Solution:

Let's name the three consecutive numbers as y, y + 2, and y + 4.

<u>Note that:</u>

  • => Equation formed: 3(y) = 2(y + 4)

<u>Solve the equation to find the three consecutive numbers.</u>

  • 3(y) = 2(y + 4)
  • => 3y = 2y + 8
  • => 3y - 2y = 8
  • => y = 8

The numbers are 8, 10, and 12.

4 0
2 years ago
Point E is between points D and F. If DE = x - 4 , EF = 2x + 5 , and DF = 4x- 8 , find x
horsena [70]
You know that 
DE+EF=DF&#10;(x-4) + (2x+5) = (4x-8)&#10;

combine like terms3x+1 = 4x-8&#10;1 = x-8&#10;x=9
3 0
3 years ago
Un camion transporta aceite de oliva en un deposito con forma de cilindro de 1m de radio y 5m de altura . Si en cada viaje que r
goldfiish [28.3K]

Answer:

15.71 metros cúbicos de aceite transportará el depósito del camión.

Step-by-step explanation:

Un camión transporta aceite de oliva en un deposito con forma de cilindro de 1 m de radio y 5 m de altura.

Para calcular la cantidad de aceite que transportará se debe calcular el volumen del depósito, siendo con forma de cilindro. El volumen de dicha figura es calculada como V=π*r²*h, donde r es el radio y h es la altura.

En este caso, el volumen del depósito cilíndrico es:

V=π*( 1 m)²*5 m

Resolviendo:

V=15,71 m³

<u><em>15.71 metros cúbicos de aceite transportará el depósito del camión.</em></u>

4 0
3 years ago
What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1
7nadin3 [17]
Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0) 
</span>
Explanation:
Given function:
f(x) =  \frac{3x^2 + x - 4}{x-1}

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \  ~ x =  \frac{-4}{3} \\ Hence~zeros=(  \frac{-4}{3}, 0)

5 0
3 years ago
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