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ratelena [41]
3 years ago
11

Who try to play quizizz with me

Mathematics
2 answers:
algol [13]3 years ago
5 0

Answer: no thanks im good

storchak [24]3 years ago
4 0

Answer:

me

Step-by-step explanation:

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Write a compound inequality to represent all of the numbers between -4 and 6.
OlgaM077 [116]
-4<x<6
should be the correct answer because x is larger than -4 but 6 is larger than x.
you could also write it
-4<x AND x<6
6 0
3 years ago
Follow the steps above and find c, the total of payments of the payments, and the monthly payment. Choose the right answers. Jan
Alex_Xolod [135]
Whats the answers people come on
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3 years ago
Harry fills up his Jeep with gasoline and notes that the odometer reading is miles. The next time he fills up his Jeep, he pays
lukranit [14]

Complete question :

Harry fills up his Jeep with gasoline and notes that the odometer reading is 23,568.7 miles. The next time he fills up his Jeep, he pays for 12.6 gallons of gasoline. He notes his odometer reading is 23,706.3 miles. How many miles per gallon did he get?

Answer:

10.9 miles per gallon

Step-by-step explanation:

Given that :

Odometer reading when filled up with gasoline = 23,568.7 miles

Odometer reading with 12.6 gallons of gasoline = 23,706.3 miles

Miles per gallon gotten :

(Current Odometer reading - reading when filled up) / gallon of gasoline

(23706.3 - 23568.7) / 12.6

= 10.920634

= 10.9 miles per gallon

6 0
2 years ago
Please help :( <br><br>4•x=28<br><br>(I'm kinda dum so this is hard)​
Oduvanchick [21]
4x = 28

28 divided by 4 = 7

x = 7

4•7=28 (TRUE STATEMENT)
7 0
2 years ago
Read 2 more answers
The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

5 0
2 years ago
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