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denis23 [38]
3 years ago
13

In ΔOPQ, the measure of ∠Q=90°, OQ = 20, PO = 29, and QP = 21. What is the value of the sine of ∠P to the nearest hundredth?

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

0.69

Step-by-step explanation:

OQ/sin(P) = OP/sin(Q)

20/sin(P) = 29/sin(90)

sin(P) = 20/29

sin(P) = 0.6896551724

Rufina [12.5K]3 years ago
3 0

Answer:

  0.69

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that the sine is the ratio ...

  Sin = Opposite/Hypotenuse

For angle P, the opposite side is OQ. The hypotenuse is the longest side, PO. So, the sine is ...

  sin(P) = OQ/PO = 20/29

  sin(P) ≈ 0.69

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