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Charra [1.4K]
2 years ago
12

Find an equation of variation in which y varies directly as x and y=1 when x=0.5. Then find the value of y when x = 14.

Mathematics
1 answer:
FromTheMoon [43]2 years ago
8 0

<u>Part 1</u>

The value of y is twice that of x, so the equation is y = 2x.

<u>Part 2</u>

Substituting in x = 14, we get y = 2(14) = 28.

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Step-by-step explanation:

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There are 4,000 books in the town's library. Of these 2,600 are fiction. Write a percent equation that you can use to find the p
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Answer:

x = (2600/4000) × 100%

x = 0.65 × 100%

x = 65%

Step-by-step explanation:

The percentage equation that can be used to find the percent of books that are fiction can only be found where the number of fiction books is known and the total number of books available is known as well.

Given;

Number of fiction books = 2,600

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WILL CHOOSE BRAINLIEST. Use the picture and the sentence in the white box to find the combination.
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It’s ‘ I like you’

Step-by-step explanation:

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I don’t know how to do this if your smart help me (I’m dumb)
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Answer:

8x= y

Step-by-step explanation:

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3 years ago
Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

mean ( u ) = 8 ounces

std ( б )= 1.5

navel oranges = X

A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

                   = P ( Z > 2.33 ) = 0.0099

                   = 0.9%

B) percentage of oranges weighing less than 8.7 ounces

  P( x < 8.7 ) = P ( \frac{x - u}{ std} > \frac{8.7-8}{1.5} )

                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

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