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Mariana [72]
3 years ago
9

Joe learned that decaying plants produce an acidic environment. Joe wants to know if pill bugs prefer acidic environments instea

d of environments that are neutral. He prepares an aquarium for the pill bugs that is divided into two sections: Side 1 contains a moist paper towel with neutral pH water. Side 2 contains a moist paper towel with hydroelectric acid (HCl). The divider that separates the two sides of the aquarium has openings to allow the pill bugs to move back and forth. Joe placed half the pill bugs in Side 1 and the other half into Side 2. Joe collects the data every two minutes as shown below. Pill Bugs in the Experimental Aquarium Capture. PNG What can Joe infer from the data recorded? Pill bugs prefer to live in decaying material. Pill bugs prefer to live in groups of ten or more. Pill bugs prefer to live in an environment with direct sunlight. Pill bugs prefer to live in a dry environment with little moisture..
Physics
2 answers:
Sati [7]3 years ago
8 0

Answer:

I'm pretty sure the answer is that the pill bugs prefer to live in a dry environment with little moisture. I don't know if i'm right, and i'm really sorry if it's wrong :((

Explanation:

Anna11 [10]3 years ago
6 0
Yessgshhshe the answer
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3 0
3 years ago
BEST ANSWER GETS BRAINLIEST!
wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
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Leno4ka [110]

Answer:

Well my good friend the other person did not give U a good answer, it is actually the third one

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3 0
4 years ago
2.
Afina-wow [57]

Answer:

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q................... Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V................ Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

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3 years ago
What must be true about two objects if heat is flowing between them? the objects must be different temperatures. the objects mus
VladimirAG [237]
They must have different temperatures.
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4 years ago
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