Complete Question
A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)
Answer:
The velocity is
Explanation:
From the question we are told that
The magnitude of the electric field is 
The magnetic field is 
The force due to the electric field is mathematically represented as

and
The force due to the magnetic field is mathematically represented as

Now given that it is perpendicular , 
=> 
=> 
Now given that it is not deflected it means that

=> 
=> 
substituting values


The answer is B. Gases and particles in earth’s atmosphere scatter sunlight in all directions
Answer:
trade winds
Explanation:
In tropics regions on the lower portion of earth's atmosphere the surface winds are observed in prevailing pattern. In northern hemisphere the trade wind predominantly blows from north east. In southern hemisphere it flows from south east. Subtropical high and the equator is in between these areas.
Thus, trade wind blow between the subtropical high and the equator.
Answer:
your questions are not clear
The answer is letter C. 1.2 10^-11 N up
Solution:
F= Bqvsin(theta)
theta = sin 90 = 1
F= 1.4 T * 1.6x10^-19 * 5.2x10^7 ms^-1
F= 1.16 x 10^-11 N
Then the direction is upward.