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Anna35 [415]
3 years ago
13

BEST ANSWER GETS BRAINLIEST!

Physics
1 answer:
wel3 years ago
8 0

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

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A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.
snow_lady [41]

Complete Question

A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)

Answer:

The velocity is  v =  3.79 *10^{5} \ m/s  

Explanation:

From the question we are told that

    The  magnitude of the electric field is  E  =  144 \ kV /m   =  144*10^{3} \  V/m

     The magnetic field is  B  =  0.38 \ T

   

The force due to the electric field is mathematically represented as

      F_e =  E  * q

and

The force due to the magnetic field is mathematically represented as

    F_b  =  q * v  *  B * sin(\theta )

Now given that it is perpendicular ,  \theta  = 90

=>   F_b  =  q * v  *  B * sin(90)

=>   F_b  =  q * v  *  B

Now  given that it is not deflected it means that

        F_ e  =  F_b

=>    q *  E = q *  v  * B

=>   v =  \frac{E}{B }

 substituting values

     v =  \frac{ 144 *10^{3}}{0.38 }

     v =  3.79 *10^{5} \ m/s

7 0
3 years ago
Why is the sky blue
ZanzabumX [31]
The answer is B. Gases and particles in earth’s atmosphere scatter sunlight in all directions
6 0
3 years ago
Which surface winds blow between the subtropical high and the equator
sasho [114]

Answer:

trade winds

Explanation:

In tropics regions on the lower portion of earth's atmosphere the surface winds are observed in prevailing pattern. In northern hemisphere the trade wind predominantly blows from north east. In southern hemisphere it flows from south east. Subtropical high and the equator is in between these areas.

Thus, trade wind blow between the subtropical high and the equator.


7 0
3 years ago
Read 2 more answers
Plss be qauick i give brainliest
irakobra [83]

Answer:

your questions are not clear

3 0
3 years ago
What is the magnetic force on a proton that is moving at 4.5 107 m/s to the right through a magnetic field that is 1.6 T and poi
pickupchik [31]
The answer is letter C. 1.2 10^-11 N up
Solution:
F= Bqvsin(theta)
theta = sin 90 = 1
F= 1.4 T * 1.6x10^-19 * 5.2x10^7 ms^-1
F= 1.16 x 10^-11 N
Then the direction is upward.
6 0
3 years ago
Read 2 more answers
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