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sergejj [24]
3 years ago
15

What must be true about two objects if heat is flowing between them? the objects must be different temperatures. the objects mus

t be the same temperature. the objects must both be over room temperature. the objects must both be under room temperature.
Physics
2 answers:
tester [92]3 years ago
7 0

Heat always flows from high temperature to low temperature and flows until the temperature between the two locations become equal. hence for the two objects having heat flowing between them, the temperature must be different. one object must have higher temperature than the other object.

hence the correct choice is

the objects must be different temperatures

VladimirAG [237]3 years ago
4 0
They must have different temperatures.
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Colt1911 [192]

Answer:

you don't have to its your choice whether you want to or not.

Explanation:

but you can not leave the fact that there dieing

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Question : Is it possible for heat to transfer from T3 to T1 and why?
fomenos

Answer:

no its a negative

Explanation:

because they both are positive

6 0
3 years ago
A 7750 kg space probe, moving nose-first toward Jupiter at 179 m/s relative to the Sun, fires its rocket engine, ejecting 72.0 k
Reika [66]

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute

7750(179)+72(230) = (7750+72)v

1,387,250+16560 = 7822v

1,403,810 = 7822v

v = 1,403,810/7822

v= 179.47m/s

Hence the final velocity of the probe is 179.47m/s

7 0
2 years ago
A thin, metallic spherical shell of radius 0.347 m0.347 m has a total charge of 7.53×10−6 C7.53×10−6 C placed on it. A point cha
USPshnik [31]

Answer:

E = 12640.78 N/C

Explanation:

In order to calculate the electric field you can use the Gaussian theorem.

Thus, you have:

\Phi_E=\frac{Q}{\epsilon_o}

ФE: electric flux trough the Gaussian surface

Q: net charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:

\Phi_E=EA=E(4\pi r^2)=\frac{Q}{\epsilon_o}\\\\E=\frac{Q}{4\pi \epsilon_o r^2}

r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m

Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:

Q=7.53*10^{-6}C+3.65*10^{-6}C=1.115*10^{-5}C

Finally, you obtain for E:

E=\frac{1.118*10^{-5}C}{4\pi (8.85*10^{-12C^2/Nm^2})(0.795m)^2}=12640.78\frac{N}{C}

hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C

3 0
3 years ago
Which type of ocean sediment contains the remains of dead organisms?
konstantin123 [22]
The <span>biogenous sediment contains the remains of dead organisms such as shells and skeletons.</span>
4 0
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