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sergejj [24]
4 years ago
15

What must be true about two objects if heat is flowing between them? the objects must be different temperatures. the objects mus

t be the same temperature. the objects must both be over room temperature. the objects must both be under room temperature.
Physics
2 answers:
tester [92]4 years ago
7 0

Heat always flows from high temperature to low temperature and flows until the temperature between the two locations become equal. hence for the two objects having heat flowing between them, the temperature must be different. one object must have higher temperature than the other object.

hence the correct choice is

the objects must be different temperatures

VladimirAG [237]4 years ago
4 0
They must have different temperatures.
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a jetliner goes from rest to a takeoff speed of 162 mi/h in 39.5 s. what is the magnitude of its average acceleration?
irakobra [83]
Acceleration = V/t

First set velocity to m/s

V = 72.42 m/s

Now we divide velocity by time

A = 72.42/39.5
A = 1.83 m/s^2
3 0
3 years ago
A rocket moves upward, starting from rest with an acceleration of +30.0 m/s2 for 5.00 s. It runs out of fuel at the end of this
olchik [2.2K]

Answer:

The distance covered by the rocket after fuel ran out is 3442.04 m

Explanation:

Given that the rocket moves with an acceleration a=30m/s^2

time t=5 s

Since the rocket starts from rest initial velocity  u=0 s

The distance it travelled within this time is given by  s=ut+ \frac{1}{2} at^2                                                                                                  =0 \times 5+ \frac{1}{2} (30\times25)=375 m

Velocity at this point is given by v=u+at

v=0+30\times5=150m/s

Given that at this height it runs out of fuel but travels further. Here final velocity v=0(maximum height), initial velocityu=150 m/s  and time to zero velocity t=\frac{v}{g} = \frac{150}{9.8} =15.3 s.

Thus it travels 15.3 seconds more after fuel running out. The distance covered during this period is given

s= ut+\frac{1}{2} gt^2=150 \times 15.3+1/2 \times9.8 \times 15.3^2=3442.04 m

7 0
3 years ago
In concave mirror, the size of image depends upon
irina1246 [14]

Answer:

The distance of the object placed on the principal axis from the concave mirror.

Explanation:

In a concave mirror, the nature of the image formed formed by the object placed in front of the mirror depends on the position of the object placed in from of the mirror. It all depends on the distance between the mirror and the object placed on the principal axis.

The closer the object is to the lens, the more larger or magnified the image formed will be. For example an object placed between the focal point and the pole of a concave produces a much larger image than an object placed beyond the centre of curvature of such mirror.

8 0
3 years ago
Read 2 more answers
4. A student wants to determine what type of cereal his classmates like best. He buys 3 boxes of his most favorite puffed rice c
Ann [662]
D
The student's conclusion shows experimental bias
Just because most of nis classmates like puffed cereal ,it is inappropriate to conclude puffed cereal is better than oats cereal
4 0
3 years ago
A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
rusak2 [61]

Answer:

Spring constant in N / m = 6,000

Explanation:

Given:

Length of spring stretches = 5 cm = 0.05 m

Force = 300 N

Find:

Spring constant in N / m

Computation:

Spring constant in N / m = Force/Distance

Spring constant in N / m = 300 / 0.05

Spring constant in N / m = 6,000

8 0
3 years ago
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