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slava [35]
3 years ago
8

2. (Free-fall problem) A ball is thrown up in the air. 10 seconds later it reaches the top of its trajectory. What was the origi

nal velocity it was thrown upward with?​
Physics
1 answer:
Sever21 [200]3 years ago
8 0

Explanation:

Using kinematics,

t = 10s

v = 0m/s

a = -9.8m/s^2

Therefore u = v - at = 0 - (-9.8)(10) = 98m/s.

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Answer:

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from that height it will just be subjected to the gravitational acceleration 
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EastWind [94]

Answer:

A

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2 years ago
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4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
xxMikexx [17]
14-6 =8
8/4= 2m/s per second
8 0
3 years ago
Read 3 more answers
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