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yanalaym [24]
3 years ago
10

Consider the three functions: f(x) = Three-halves(4)x g(x) = Three-halves(4)–x h(x) = –Three-halves(4)x Which statements are tru

e about the domain and range of f(x), g(x), and h(x)? Check all that apply. f(x) has a domain of all real numbers. g(x) has a range of y < 0. h(x) has a range of y > 0. g(x) has a domain of all real numbers. h(x) has a domain of x > 0.
Mathematics
2 answers:
charle [14.2K]3 years ago
8 0

The correct option is;

The ranges of f(x) and h(x) are similar and different from the ranges of g(x)

Step-by-step explanation:

Here we have the functions given as follows;

f(x) = -6/11 (11/2)ˣ

g(x) = 6/11 (11/2)⁻ˣ

h(x) = -6/11 (11/2)⁻ˣ

from the above equations, it can be seen that f(x) and h(x) are always negative while g(x) is always positive

f(x) and h(x) are symmetric about the y axis while g(x) and h(x) are symmetric about the x axis

Also h(x) is the inverse of f(x) hence the ranges of f(x) and g(x) are similar and are different from the ranges of g(x).

Gemiola [76]3 years ago
4 0

Answer:

A and D

Step-by-step explanation:

A.) f(x) has a domain of all real numbers.

D.) g(x) has a domain of all real numbers.

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Samir ran for 10 minutes, stopped and stretched for 5 minutes, walked for 20 minutes, and ran for another 15 minutes.
Natasha2012 [34]

Answer:

The total time he was out was 50mins if thats what u wanted to know....

10+5+20+15=50mins

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4 years ago
Identify the inequality that matches the graph
pogonyaev
I believe that C would be you’re answer
8 0
3 years ago
What is the mean of 22,37,49,15,82?
Alex73 [517]
Mean = ( 22 + 37 + 49 + 15 + 82 ) /  5
           = 41

Hope this helps  :)
6 0
4 years ago
Read 2 more answers
The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

So, the hypotenuse decreases H - H' \approx 17 - 14.3 = 2.7

3 0
3 years ago
What is y &lt;-x+2 on a graph???
sertanlavr [38]
Tada! Hope that helps. :)

3 0
3 years ago
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