V=area of base times height
height=height
area of base=area of circle=pir^2
V=hpir^2
r=6
h=14
V=14pi6^2
V=14pi36
V=504pi
aprox pi=3.141592
V=1583.3 round
V=1583 cm^3
Answer:
Relative error = 0.0254 %
Step-by-step explanation:
Given details
Height of equipment from base is 104 ft
Elevation angle is 27.5 degree
From figure we have
.........1

x = 54.13 ft
differentiating 1st eq wrt x
![\frac{d}{dx} tan\theta = \frac{d}{dx} [\frac{x}{104}]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20tan%5Ctheta%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bx%7D%7B104%7D%5D)

Taken
for minute change


from 



Reltaive error

Relative error = 0.0254 %
You are multiplying by 3 each time. This sequence is geometric.
9 = 3*3 = 3^2
27 = 3*9 = 3*3*3 = 3^3
81 = 3*27 = 3*3*3*3 = 3^4
and so on.
The general rule is 3^x which is choice D
The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.
Looking at each the polynomial:
3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)
2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)
8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4: Degree is 6 (look at 1st term)
–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5: Degree is 6 (look at 1st and last term)
Therefore, the answer is the second option:
2xy4 + 4x2y3 – 6x3y2 – 7x4