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AlekseyPX
3 years ago
15

How do you write 5-n

Mathematics
2 answers:
enot [183]3 years ago
8 0

5 - n written in word form is:

Five minus a number, n.

vlabodo [156]3 years ago
6 0

Answer:

  You have done a good job of it

Step-by-step explanation:

Here's one way:

  5-n

Here's another way:

  -n+5

In words, this might be described as ...

  "the difference between 5 and n".

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ANSWE PLEASEEEEEEEEEEEEEEE
Natalka [10]

Answer:

your answer is gonna be A!! <3

Step-by-step explanation:

1 Subtract 33 from both sides.

y-3=-2x

y−3=−2x

2 Divide both sides by -2−2.

-\frac{y-3}{2}=x

−

2

y−3

=x

3 Switch sides.

x=-\frac{y-3}{2}

x=−

2

y−3

5 0
2 years ago
One number is 3 more then twice another. The sum of the numbers is 12
aev [14]
It’s 9. 9+3=12
3,6,9,12
The twice of 3 is six more than twice is nine.
3 0
3 years ago
How many different 3-digit PIN codes are there that only include the digits 7, 4, 3 and 2?
KengaRu [80]

Answer:

64

Step-by-step explanation:

We can use the product rule of counting to answer this:

There are 4 possibilities for the 1st digit
There are 4 possibilities for the 2nd digit
There are 4 possibilities for the 3rd digit
So we use the product rule of counting to give us:

4×4×4=64

6 0
2 years ago
83/10y-(38/11-11/4y)
IrinaK [193]

Answer:

I think 83 ÷ 10 and it said that it incorrect

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
When we test Upper H 0​: muequals0 against Upper H Subscript a​: mugreater than​0, we get a​ P-value of 0.03. a. What would the
Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

(c) The null hypothesis will not be rejected. The error is type II error.

Step-by-step explanation:

The hypothesis provided is:

H_{0}: \mu = 0\\ H_{a} : \mu > 0

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

p-value = 0.03 < \alpha  = 0.10

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in​ (a) is an​ error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

p-value = 0.03 > \alpha  = 0.01

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0
3 years ago
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