Question

What is the vertex of y=2x^2

Answer 1

Use the vertex form, y=a(x−h)2+k y = a ( x - h ) 2 + k , to determine the values of a a , h h , and k k . Since the value of a a is positive, the parabola opens up. Find p p , the distance from the vertex to the focus. Find the distance from the vertex to a focus of the parabola by using the following formula.

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Answer 2

Answer:

Step-by-step explanation:

It is a first cousin to y=x^2. The only difference is the 2 in front of the x^2 which narrows x^2.

The vertex is at (0,0)