Answer:
No
Step-by-step explanation:
I don't think that's how those specifc diagrams work. X in this case would be 3 not seven.
Yes you can move the x and the 1s but it would break the whole diagram. It would just be an (expression/term). Not a full diagram.
You said this was 7th grade math? Wow. I learned this in 5th grade!
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
Answer:
1.512445e+216
Step-by-step explanation:
A) The first one equals to 5
Step by step:
Change all denominators to 28, what you do to the bottom you do to the top.
After adding simplify.