The speed of the driver is 200km/hr.
<h3>How to calculate the speed?</h3>
The information is incomplete and an overview will be given since the complete information wasn't found online.
It should be noted that speed is calculated as:
= Distance / Time
Let distance = 2000km
Let time = 10 hours.
Speed = Distance/Time
Speed = 2000/10
Speed = 200km/hr
Learn more about speed on:
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3 +250= 253 take 253 dived it by 3 ,subtract 4 =80.3
<span>Answer: A) exponential, because there is a relatively consistent multiplicative rate of change
</span><span>
temperature thrice. If you compare time=0 until time=30, you will get this table
t(10)- t(0)= 180-200= -20
t(20)-t(10)= 163-180= -17
t(30)-t(20)= 146-163= -17
</span>t(40)-t(30)= 131- 146= -15
t(50)-t(40)= 118-131= -13
t(50)-t(40)= 107-118= -11
There is something weird about the 2nd and 3rd value because it was same -17., but there seems to be a +2 change to the difference. So, the graph would be exponential with a <span>relatively consistent multiplicative rate of change</span>
Answer:
56 eggs
Step-by-step explanation:
If
of all eggs are green,
of all are blue, then

of all eggs are red.
We know that there are 26 red eggs
![26\text{ eggs }-\dfrac{13}{28}\\ \\x\text{ eggs }- 1[=\dfrac{28}{28}]](https://tex.z-dn.net/?f=26%5Ctext%7B%20eggs%20%7D-%5Cdfrac%7B13%7D%7B28%7D%5C%5C%20%5C%5Cx%5Ctext%7B%20eggs%20%7D-%201%5B%3D%5Cdfrac%7B28%7D%7B28%7D%5D)
Make a proportion
![\dfrac{26}{x}=\dfrac{\frac{13}{28}}{1}\\ \\26\cdot 1=x\cdot \dfrac{13}{28}\ [\text{Cross multiply}]\\ \\13x=26\cdot 28\ [\text{Multiply by 28 to get rid of fraction}]\\ \\x=\dfrac{26\cdot 28}{13}\ [\text{Divide by 13 to get x}]\\ \\x=2\cdot 28\\ \\x=56](https://tex.z-dn.net/?f=%5Cdfrac%7B26%7D%7Bx%7D%3D%5Cdfrac%7B%5Cfrac%7B13%7D%7B28%7D%7D%7B1%7D%5C%5C%20%5C%5C26%5Ccdot%201%3Dx%5Ccdot%20%5Cdfrac%7B13%7D%7B28%7D%5C%20%5B%5Ctext%7BCross%20multiply%7D%5D%5C%5C%20%5C%5C13x%3D26%5Ccdot%2028%5C%20%5B%5Ctext%7BMultiply%20by%2028%20to%20get%20rid%20of%20fraction%7D%5D%5C%5C%20%5C%5Cx%3D%5Cdfrac%7B26%5Ccdot%2028%7D%7B13%7D%5C%20%5B%5Ctext%7BDivide%20by%2013%20to%20get%20x%7D%5D%5C%5C%20%5C%5Cx%3D2%5Ccdot%2028%5C%5C%20%5C%5Cx%3D56)