All categories

3 years ago

How many grams are needed to form 33.6 L of carbon dioxide

1 answer:

7 0

It depends of the temperature and the pressure. If temperature and pressure are standard 1 mol forms 22.4 liter. So 33.6 liters form 33.6/22.4 = 1.5 mols.

Now calculate the molar mass of carbon dioxide: 12 g/mol + 2x16 g/mol = 44 g/mol

The mass of the 1.5 mols is 1.5mol * 44 g/mol = 66 g.

You might be interested in

What is a synthesis reaction? a reaction that occurs when two or more reactants combine into one product

dmitriy555 [2]

Answer:

A synthesis reaction is <em>a reaction that occurs when two or more reactants combine into one product.</em>

Explanation:

A reaction that occurs when two or more reactants combine into one product is called a synthesis reaction.

A reaction that occurs when one element within a compound is exchanged with another element is called a single replacement reaction.

A reaction that occurs when a substance combines with molecular oxygen, releasing light and energy is called combustion.

A reaction that occurs when a single substance breaks apart and forms two or more new substances is called decomposition.

7 0

3 years ago

If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of sand, what percent by mass of

n200080 [17]

We are given with a mixture of sand and table sugar. The mixture has a mas s of 3.84 grams. After recovery, it was found out that there is 1.43 grams of sand. The amount of table sugar then is 3.84-1.43 or 2.41 grams. This is equal to 2.41/3.84 or 62.76% by mass/

4 0

3 years ago

A sugar cube was placed into a beaker containing 100 mL of water at room temperature and completely dissolved into the water. Th

Bad White [126]

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

3 0

3 years ago

If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?

Ostrovityanka [42]

Answer : The rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

Explanation : Given,

Moles of $S_2O_2^{-8}$ = $2.0\times 10^{-4}mol$

Volume of solution = 170 mL = 0.170 L (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

$\text{Concentration}=\frac{\text{Moles}}{\text{Volume of solution}}$

$\text{Concentration}=\frac{2.0\times 10^{-4}mol}{0.170L}$

$\text{Concentration}=1.2\times 10^{-3}M$

Now we have to calculate the rate of consumption.

$\text{Rate of consumption}=\frac{\text{Concentration}}{\text{Time}}$

$\text{Rate of consumption}=\frac{1.2\times 10^{-3}M}{170s}$

$\text{Rate of consumption}=7.0\times 10^{-6}M/s$

Thus, the rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

8 0

3 years ago

Ann drove to the store km north of her house and then drove to the library, which is 5 km south of the store. She drove a total

Vadim26 [7]

Answer : The question is incomplete, the complete question is attached in answer

To calculate the displacement by Ann's driving from north of her house to south;

we have the data as

In north - 10 km
in south - 5 km
total - 15 km

So we can calculate the displacement, which will be,

10 - 5 = 5 km.

Hence, the displacement will be 5 km

3 0

3 years ago