Ann drove to the store km north of her house and then drove to the library, which is 5 km south of the store. She drove a total
distance of 15 km. What was Ann’s displacement?
1 answer:
Answer : The question is incomplete, the complete question is attached in answer
To calculate the displacement by Ann's driving from north of her house to south;
we have the data as
In north - 10 km
in south - 5 km
total - 15 km
So we can calculate the displacement, which will be,
10 - 5 = 5 km.
Hence, the displacement will be 5 km
To calculate the displacement by Ann's driving from north of her house to south;
we have the data as
In north - 10 km
in south - 5 km
total - 15 km
So we can calculate the displacement, which will be,
10 - 5 = 5 km.
Hence, the displacement will be 5 km
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Answer:
1.7 Osm/L
Explanation:
Osmotic concentration is the number of osmoles (Osm) of solute per litre of solution .
An osmole is the number of moles of solute that contribute to the osmotic pressure of a solution.
1 Osm = i × n, where
i = the van't Hoff i factor and
n = the number of moles
The van't Hoff i factor is the number of solute particles obtained from 1 mol of solute.
For example,
MgSO₄(aq) ⟶ Mg²⁺(aq) + SO₄²⁻(aq)
1 mol of MgSO₄ produces 2 mol of ions in solution, so i = 2.