Answer:
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
pH = 9.6
Explanation:
Step 1: Given data
Concentration of OH⁻ in the solution ([OH⁻]): 4.0 × 10⁻⁵ M
Step 2: Calculate the concentration of H₃O⁺ in the solution
Let's consider the self-ionization of water.
2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻(aq)
The <em>ion-product of water (Kw)</em> is:
<em>Kw = 1.0 × 10⁻¹⁴ = [H₃O⁺] × [OH⁻]</em>
[H₃O⁺] = 1.0 × 10⁻¹⁴/[OH⁻]
[H₃O⁺] = 1.0 × 10⁻¹⁴/4.0 × 10⁻⁵
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
Step 3: Calculate the pH of the solution
We will use the following expression.
<em>pH = -log [H₃O⁺]</em>
pH = -log 2.5 × 10⁻¹⁰
pH = 9.6
Its quite alot of work, but here it is....
1. Silver Nitrate: AgNO3 (aq)
<span>Potassium Chloride: KCl </span>
<span>To do a double replacement reaction, switch the two metals around, in this case Silver and Potassium so you are left with: </span>
<span>Potassium Nitrate: KNO3 </span>
<span>Silver Chloride: AgCl </span>
<span>The chemical equation should be something like this: </span>
<span>AgNO3 (aq) + KCl => KNO3 + AgCl
</span>
2The chemical reaction is as follows:Al2(SO4)3 + 3Ca(OH)2 → 3CaSO4 + 2Al(OH)3 Explanation:1mol of Al2(SO4)3 will react with 3mol Ca(OH)2 to produce 3mol CaSO4 and 2 mol Al(OH)3.First we have to find the number of moles of Al2(SO4)3 :Number of moles = Mass/ Molar massMass of Al2(SO4)3 = 500gMolar mass of Al2(SO4)3 = 342.15 g/molNumber of moles = 500/342.15Number of moles = 1.461 mol Al2(SO4)3Multiplying the coeffecient of Ca(OH)2 with 1.461:= 3*1.461 = 4.383 mol Ca(OH)2 Now we have to find the number of moles of Ca(OH)2:Mass of Ca(OH)2 = 450gMolar mass of Ca(OH)2 = 74.09 g/mol Number of moles = 450/74.09Number of moles = 6.074 mol Ca(OH)2We need 4.383mol to react completely with the Al2(SO4)3, so the Ca(OH)2 is in excess, and the Al2(SO4)3 is the limiting reactant. Excess unreacted: 6.074-4.383 = 1.69mol Ca(OH)2 unreacted
<h2>The number of moles of formaldehyde can be produced by reacting 4.0 moles of methanol with 4.0 moles of oxygen gas is
<u>
8 moles</u></h2>
<u> explanation</u>
write a balanced chemical reaction
that is 2 CH3OH (l) + O2 (g) → 2HCOH (l)+ 2H2O (l)
from the reaction above 2 moles of CH3OH reacted with 1 moles of O2 to form 2 moles of HCOH and two moles of H2O
This imply that O2 is the limiting reagent ,therefore by use of mole ratio between O2 : HCOH which is 1 :2 the moles of HCOH= 2 x4 = 8 moles
Answer:
heat flows from the object that has more thermal more energy to the object with less thermal energy
Answer:
a) Br-, Kr, Sr2+
Explanation:
plus and minus sort of mean opposite here
Br has 35
Br- has 36
Sr has 38
Sr2+ has 36
Kr has 36
in which of the following sets do all species have the same number of electrons (isoelectronic)?
a) Br-, Kr, Sr2+
b) C, N3-, O2-
c) Mg2+, Sr2+, Ba2+
d) O, O2-, O2+
Mg2+ has 10
Sr2+ has 36
Ba2+ has 54
Br- has 36
Kr has 36
Sr2+ has 36
C has 6
N3- has 10
O2- has 10
O has 8
O2+ has 6
toppr