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AnnZ [28]
2 years ago
5

In how many ways can 4 different novels, 2 different mathematics books, and 1 biology book be arranged on a bookshelf if the nov

els must be together but the other books can be arranged in any order?
Mathematics
1 answer:
geniusboy [140]2 years ago
7 0

Answer:

Pt = 576

Step-by-step explanation:

If 4 different novels must be together, we have 4 elements then

P₁  = 4!       P₁  = 4*3*2*1

 P₁  =  24

But now we have to consider  position between the novel group

P₂  =  4!      P₂    =  24

Total ways

Pt  =  24*24

Pt = 576

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Step-by-step explanation:

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mylen [45]

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7 0
2 years ago
The perimeter of a rectangle is 215 feet. The short sides are each 24 feet long, but the lengths of the long sides are unknown.
Nataly_w [17]

Answer:

2 ( 24 ) + 2 a = 215

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6 0
3 years ago
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5 0
2 years ago
Can someone help me ?
Lapatulllka [165]

Answer:

A) 1/6

Step-by-step explanation:

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