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Ghella [55]
3 years ago
13

Its -3 right I'm not sure ?

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

Answer: 3 or -1

Step-by-step explanation:

(q-2)(q+3) = 3(q-1)

q^2+x-6 = 3x-3

q^2-2x-3 = 0

(q-3)(q+1) = 0

q = 3 and -1

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What is the percent of change from 50 to 11?
maxonik [38]

Answer: 22% *nevermind :(*

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
April took out a $600 loan from the bank. At the end of 5 years, she pays
Bingel [31]

Answer:

2%

Step-by-step explanation:

$60 is 10% of $600

If you divide that 10% by the 5 years you get 2%

3 0
3 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
3 years ago
I WILL GIVE BRAINLIEST!!!
anzhelika [568]
All I see is A
But the answer is this
Look for a graph like this

3 0
3 years ago
Find the distance between the points A(13,2) and B(7,10)
Anna007 [38]

Answer:

10 = D

Step-by-step explanation:

Method #1

We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:

{a}^{2} + {b}^{2} = {c}^{2}

{6}^{2} + {8}^{2} = {c}^{2}

36 + 64 = {c}^{2}

100 = {c}^{2}

10 = c

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

_______________________________________________

Method #2

Or, we can use the Distance Formula:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

<em>B</em>[7, 10] <em>A</em>[13, 2]

\sqrt{[-2 + 10]^{2} + [-13 + 7]^{2}} = D

\sqrt{8^{2} + [-6]^{2}} = D

\sqrt{64 + 36} = D

\sqrt{100} = D

10 = D

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

** You see? It does not matter which method you choose, as long as you are doing the work correctly.

I am delighted to assist you anytime.

6 0
4 years ago
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