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salantis [7]
3 years ago
5

Three times a number is three more than twice the number. Which equation can be used to find the value of x, the unknown number?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0

3x = 2x + 3. I hope this helps! Could I possibly get brainliest?


Umnica [9.8K]3 years ago
6 0

The answer is 3x+3(2)


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A plot of land doubles in size by adding x meters to the length and x meters to the width of the land.If the original plot had a
Soloha48 [4]

Answer:

  100

Step-by-step explanation:

The original area is (200 m)×(300 m) = 60000 m². You want an area that is ...

  (200 +x)×(300 +x) = 120000

  60000 +500x +x² = 120000 . . . . eliminate parentheses

  x² +500x -60000 = 0 . . . . . . . . . . subtract 120000

  (x +600)(x -100) = 0 . . . . . . . . . . . . factor

The positive value of x that makes a factor zero is x = 100.

The value of x is 100.

_____

<em>Check</em>

The larger plot will be 300×400, the larger dimension being double the original smaller dimension.

3 0
3 years ago
Slove the equation -29=9-6k-2k-14
Mashcka [7]

Answer:

Step-by-step explanation:

k=3


4 0
3 years ago
five times the difference of twice a number and three, decreased by the sum of the number and eight , equals 13
kramer

Answer:

x=4

Step-by-step explanation:

5(2x-3)-(x+8)=13

10x-15-x-8=13

9x-23=13

9x=36

x=4

4 0
4 years ago
Please show your work and explain it.
Maru [420]

Answer:

f(x)=\dfrac{x+2}{2(x-2)}

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}

Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

And we can now simplify it to:

=\dfrac{x+2}{2(x-2)}

6 0
4 years ago
Y = x2 + 4<br> y = x + 6
Nataliya [291]

Answer:

X=2

Y=8

Step-by-step explanation:

Since both equations are equal to y we can equal both equations

2x+4=x+6

x=2

y=2(2)+4

y=8

4 0
3 years ago
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