The director is wrong. The lurking variable here is the temperature.
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Answer:
Graph of quadratic opening downward and linear sloping up to the left. They intersect at point negative 3, negative 1 and point 1, negative 5
Step-by-step explanation:
we have
we can separate the expression above into two equations
----> equation A
This is a quadratic equation ( vertical parabola) open downward (the leading coefficient is negative)
----> equation B
This is a linear equation with negative slope (decreasing function).so linear sloping up to the left
The solution of the original expression are the x-coordinates of the intersection point both graphs
using a graphing tool
The intersection points are (-3,-1) and (1,-5)
see the attached figure
