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yulyashka [42]
4 years ago
14

What is the Derivative of x^3-2

Mathematics
1 answer:
Ghella [55]4 years ago
4 0
-5 is the correct answer hope that helped you goodluck because i don’t know it lol so okay smell my butt
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How to factorize -3pa-9b-18pc
Fed [463]
-3pa - 9b - 18pc

For starters, you know that you can't take away any of the letters from the equation because none of the three have the exact same letter; however, they all have something they can be divided by and that is -3. 

It would be -3 instead of just 3 because the equation itself starts with a negative. (you could probably do it anyways with just 3, but you'd end up taking out a negative one, anyways, so what's the point?)

Now, you would have: -3 ( pa + 3b + 6pc )

That is truly all you can take out. So, that would end up being your answer since all you can really do is simplify.  
7 0
4 years ago
Please help me with acellus
nignag [31]
4x-16=2x+16
4x+2x=16+16
6x=22/6

x=3.7
8 0
3 years ago
Read 2 more answers
What is the value of r?<br><br> Enter your answer, as an exact value, in the box.
Oxana [17]
The answer is √32 because the triangle is an isosceles triangle meaning two sides are the same length so two sides are 4 and then you use the Pythagorean theorem to find the value of r 
8 0
4 years ago
Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
Quadrilateral A B C D, the measure of, angle A, angle B, angle C, angle D are a ratio of 1:2:3:4, respectively. Find the measure
Svetach [21]

Answer:

Step-by-step explanation:

The angles of a quadrilateral have to add up to equal 360.  That means that

1x + 2x + 3x + 4x = 360 and

10x = 360 so

x = 36.  Then

2x = 72 and

3x = 108 and

4x = 144

Angle A and angle D are opposite angles, as are angles B and C.  This is because opposite angles are supplementary.

8 0
3 years ago
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