Answer:
1. 4 and 4sqrt2
2. 6sqrt2 and 6sqrt2
3. 5 and 5sqrt2
4. 5sqrt2 and 5sqrt2
5. 6 and 6
6. 8 and 8sqrt2
7. sqrt3 and sqrt6
8. sqrt2 and sqrt4
Step-by-step explanation:
Take the derivative with respect to t
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
divide by w
we add sin(wt) to both sides
divide both sides by cos(wt)
OR
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be
since 2npi is just the period of cos
substituting our second soultion we get
since 2npi is the period
so the maximum value =
minimum value =
Distribute 2 to x and -2, and -6 to x and -2
2(x - 2) = 2x - 4
-6(x - 2) = -6x + 12
2x - 4 = 4x - 6x + 12
Simplify. Combine like terms
2x - 4 = (4x - 6x) + 12
2x - 4 = -2x + 12
Isolate the x. Add 4 to both sides, and 2x to both sides
2x (+2x) - 4 (+4) = -2x (+2x) + 12 (+4)
2x + 2x = 12 + 4
Simplify
4x = 16
Isolate the x. Divide 4 from both sides
4x/4 = 16/4
x = 16/4
x = 4
4 is your answer for x.
hope this helps
<span>a rectangle rhombus(parallelogram) since even a parallelogram has diagonals</span>