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Tpy6a [65]
3 years ago
12

Helicopters can land on circular pads. The area of a landing pad is 1,962.5 square feet. What is the radius of the pad? Use 3.14

to approximate pi.
Mathematics
2 answers:
notsponge [240]3 years ago
5 0

Answer:

25 ft

Step-by-step explanation:

The area of this landing pad is 1,962.5 ft², which equals πr².

We solve this equation for r²:

       1962.5 ft²

r² = -----------------  =  625 ft²

             3.14

Taking the square root of both sides, we get:

r = √(625 ft²) = 25 ft

The radius is 25 ft.

ExtremeBDS [4]3 years ago
3 0

Answer:

The answer would be 25 feet

Step-by-step explanation:

1,962.5 ft2 = 3.14 • 25 ft2

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5 0
3 years ago
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1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
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Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
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U = 6.214286657
U = 6.21
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artcher [175]

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Step-by-step explanation:

8 0
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The line segment, AB has a point C as its midpoint. If A is at (2,2) and C is at (5,4) what are the coordinates of the endpoint
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Answer:

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Given:
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x + y = 420
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x + 6x = 420 
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y = 6x
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3 years ago
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