Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tick
ets to the fall play. If the class collected $660 from ticket sales, how many student tickets were sold? The drama class sold how many tickets?
The solution is?
For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...
6a +3(a+25) = 660
9a +75 = 660
9a = 585
a = 65
(a+25) = 90
The drama class sold 90 student tickets and 65 adult tickets.
