2(4 - 2r) = -2(r + 5)
2 answers:
2(4 - 2r) = -2(r + 5)
First, divide both sides by -2. / Your problem should look like:
Second, regroup your terms. / Your problem should look like:
Third, add 4 to both sides. / Your problem should look like:
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:
Fifth, subtract r from both sides. / Your problem should look like:
Sixth, subtract 2r - r to get r. / Your problem should look like:
Answer: r = 9
First, divide both sides by -2. / Your problem should look like:
Second, regroup your terms. / Your problem should look like:
Third, add 4 to both sides. / Your problem should look like:
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:
Fifth, subtract r from both sides. / Your problem should look like:
Sixth, subtract 2r - r to get r. / Your problem should look like:
Answer: r = 9
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Answer:
c) 6
Step-by-step explanation:
This is a straight-forward application of the Law of Cosines:
... a² = b² + c² -2bc·cos(A)
... a² = 8² +11² -2·8·11·cos(32.2°) ≈ 64 +121 -176·0.8462
... a² ≈ 36.07000
... a ≈ 6.00583
The best choice is c) 6.
