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mafiozo [28]
3 years ago
5

2(4 - 2r) = -2(r + 5)

Mathematics
2 answers:
Alexus [3.1K]3 years ago
5 0
2(4 - 2r) = -2(r + 5)

First, divide both sides by -2. / Your problem should look like: -4 + 2r = r + 5
Second, regroup your terms. / Your problem should look like: 2r - 4 = r + 5
Third, add 4 to both sides. / Your problem should look like: 2r = r + 5  + 4
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:2r = r + 9
Fifth, subtract r from both sides. / Your problem should look like: 2r - r = 9
Sixth, subtract 2r - r to get r. / Your problem should look like: r = 9

Answer: r = 9

weqwewe [10]3 years ago
5 0
8-4r = -2r-10
2r-4r=-10-8
-2r = -18
<span>r = 9</span>
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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

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25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
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