All categories

3 years ago

What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?

Mathematics

2 answers:

VladimirAG [237]3 years ago

7 0

$y=x2+3x+5

fx = x2 + 3x + 5

fx = 5 + 3x + x2

fx = 5 + 3x + x2

f = 5x-1 + 3 + x

f = 5x-1 + 3 + x

f = 3 + 5x-1 + x$ <span />

kherson [118]3 years ago

3 0

The y intercept is 5

You might be interested in

Josie took a long multiple-choice, end-of-year vocabulary test. The ratio of the number of problems Josie got incorrect to the n

FrozenT [24]

Answer:

A. Josie got 36 correct answers.

B. Josie got 90 correct answers.

C. 8:36 and 20:90

D.6:27, 12:54, 30:135, among others.

e. Multiply both numbers on the ratio by the same constant integer, thereby ensuring that the resulting numbers form a ratio equivalent to the original.

Step-by-step explanation:

Very well, so the statement is that Josie got 2 problems incorrect for every 9 that she got correct. First the ask how many questions she got correct given that she missed 8 question. First, we divide the 8 question she missed by 2. Now have 4 pairs of questions that Josie missed and for every pair that she failed; Josie got 9 questions correctly. Therefore, we multiply 4 pairs of incorrect questions times 9 correct questions. So, if Josie had 8 incorrect questions, she also had 36 correct answers on her test.

In the case that Josie missed 20 questions, we divide them by two again in order to obtain the number of pairs that Josie missed. Now have 10 pairs of questions that Josie missed and for every pair that she failed; Josie got 9 questions correctly. Therefore, we multiply 10 pairs of incorrect questions times 9 correct questions. So, if Josie had 8 incorrect questions, she also had 90 correct answers on her test.

With the information we collected, we can affirm that the ratios 8:36 and 20:90 are equivalents to the original 2:9 that was stated. Other examples of equivalents ratios could be 6:27, 12/54, 30:135, among many others.

To find the equivalent ratios what we need to do is find common multiples of the numbers that conform the ratio. To do so, we can multiply both numbers by the same constant integer, thereby ensuring that the resulting numbers form a ratio equivalent to the original.

Have a nice day! :D

6 0

4 years ago

Find the sum of the first 12 terms of the geometric sequence - 2,6,-18,54,-162....

nekit [7.7K]

Answer:

Sure, the common difference is -3, but like you have to multiple it and stuff, so it goes like this: -2,6,-18,54,-162,486,-1458,4374,-13122,39366,-118,098,354294.

So then, add all of the 12 terms I stated, and that will equal to 265,720

Therefore, the sum of the first 12 terms of that geometric sequence is 265,720.

Step-by-step explanation:

6 0

3 years ago

Suppose the profit a honda dealership makes on the next 5 accords it sells are:564, 1,000, 848, 1,495, 1,348. calculate the stan

stepladder [879]

First we have to find the mean (average)
mean = (564 + 1000 + 848 + 1495 + 1348) / 5 = 5255 / 5 = 1051

now we subtract the mean from every data point, then square it
564 - 1051 = -487......-487^2 = 237169
1000 - 1051 = -51......-51^2 = 2601
848 - 1051 = -203......-203^2 = 41209
1495 - 1051 = 444......444^2 = 197136
1348 - 1051 = 297......297^2 = 88209

now find the mean of the results.....but know when ur dealing with a sample instead of the whole population, u divide by 1 number less...so instead of dividing by 5, u divide by 4.
(237169 + 2601 + 41209 + 197136 + 88209) / 4 = 566324 / 4 =
141581.....this is called ur variance

now take the square root of the variance and u have ur standard deviation
sqrt (141581) = 376.272 rounds to 376.27 <==

5 0

4 years ago

Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car

Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0

3 years ago

Help please <br><br> hekfkdnr

mamaluj [8]

Answer:

first one is -16

second is -4

I'm what the third is

5 0

3 years ago