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kotegsom [21]
3 years ago
8

Let sin(−θ)=−3/5 and tanθ>0. What is the value of cos(−θ)?

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = \frac{- 3}{5}

- sin Ф = \frac{- 3}{5}

So, sin Ф = \frac{ 3}{5}

Now, as sin Ф = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

So ,  \dfrac{\textrm perpendicular}{\textrm hypotenuse} =  \frac{ 3}{5}

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴  Base = \sqrt{16}

I.e Base = 4

Now, Cos Ф =  \dfrac{\textrm base}{\textrm hypotenuse}

So, Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Now , Since

Cos ( - Ф ) = Cos Ф

So,  Cos ( - Ф ) = Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Hence The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} . Answer

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