$\sec^2(\theta) = \tan^2(\theta) + 1\\\\\sec^2(\theta) = (\tan(\theta))^2 + 1\\\\\sec^2(\theta) = (-1)^2 + 1\\\\\sec^2(\theta) = 2\\\\\sec(\theta) = \sqrt{2}\\\\$

Note: secant is positive in quadrant Q4, when theta is between 3pi/2 radians and 2pi radians (270 degrees and 360 degrees). So that's why we don't consider the minus form of the plus minus.

5 0

2 years ago

Trigonometry, IF answer is delivered on time WILL give BRANLIEST

Lunna [17]

Answer:

x=37°

y=6

Step-by-step explanation:

(ASSUMING BD is a perpendicular bisector of AC, otherwise answers maybe be wrong)

Consider the triangle ABC:

AB is the same length as BC (marked), meaning ABC is an isosceles triangle.

Since ABC is isosceles, ∠BAC=∠BCA=53

All angles in a triangle add up to 180:

180=∠ABC + ∠BAC + ∠BCA

180= ∠ABC + 53 +53

∠ABC = 180 - 106

∠ABC = 74

Assuming BD bisects ∠ABC perfectly, x is half of ∠ABC.

x=74/2=37

If BD bisects AC perfectly, AD=DC=y=6

8 0

3 years ago