Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Answer:
C F
Step-by-step explanation:
The best, closest quotient would be 87.
The car went about 35.34 miles per gallon.(How? Divide 7.3 into 257 and you got your answer.)
Answer:
8x-6>12+2x
-8 -8
-6>12-6x
-12 -12 -12 both sied
18>-6x
18/-6>x
3>x
Step-by-step explanation:
