If an object with a volume of 105 mL and a density of 0.801 g/mL, what is the objects mass?
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Answer:
Therefore 373 mole of Al produce 746 mole of water.
Explanation:
Given reaction is
3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O
From the above reaction it is clear that 3 mole of Al produce 6 mole of water.
Therefore
3 mole of Al produce 6 mole of water.
1 mole of Al produce mole of water.
373 mole of Al produce mole of water.
= 746 mole of water.
Therefore 373 mole of Al produce 746 mole of water.
Density of the gas is 3.05 × 10⁻³ g / cm³.
<u>Explanation:</u>
Volume of the cylinder = π r² h
where r is the radius and h is the height of the height or the length of the glass tube.
Here r = 4 cm and h = 27.4 cm
Volume of the cylinder = 3.14 × 4 × 4 × 27.4 = 1376.6 cm³
We have to find the mass of the gas by subtracting the mass of the tube filled with the substance from the mass of the empty tube.
Mass of the substance = 258.5 - 254.3 = 4.2 g
We have to find the density using the formula as,
Plugin the values as,
= 3.05 × 10⁻³ g / cm³
So the Density of the gas is 3.05 × 10⁻³ g / cm³.