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Triss [41]
3 years ago
9

Driving cars lowers the pH of the oceans by _______.

Chemistry
2 answers:
Naddika [18.5K]3 years ago
6 0
A) releasing CO2 that dissolves and forms acid in the oceans (i think i'm sorry if its wrong)
balu736 [363]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

When CO_{2} is released from driving cars, some of which is absorbed by the plants but the rest of CO_{2} reacts with the sea or ocean water.

It reacts with water molecules and changes the chemistry of ocean water by lowering its pH. As it is known that when pH becomes lower then the substance becomes acidic in nature.

Thus, we can conclude that driving cars lowers the pH of the oceans by releasing CO_{2} that dissolves and forms acid in the oceans.

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A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reac
svlad2 [7]
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4 0
3 years ago
What mass is contributed by Br-79?
satela [25.4K]

Answer:

Calculate the mass of BR -79? Bromine has 2 naturally occurring isotopes (Br-79 and Br-81) and has an atomic mass of 79.904 amu

Explanation:

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6 0
3 years ago
The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?
tino4ka555 [31]
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
</span><span>1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M

The molar solubility would be </span>1.5x10^-3 M.
8 0
3 years ago
Given that w for water is 2. 4×10−14 m^2 at 37 °C. Calculate the ph of a neutral aqueous solution at 37 °c, which is the normal
alexgriva [62]

The pH of a neutral aqueous solution at 37°C is 6.8.

<h3>What is Kw? </h3>

Kw is defined as the dissociation, which is also known as self-ionization, constant of water. this is an equilibrium constant, and its expression is:

Kw = [OH⁻] . [H₃O⁺]

Neutral pH determines that the concentrations of OH⁻ and H₃O⁺ are equal.

<h3>Calculation</h3>

Let us suppose concentration of OH and H₃O⁺ is x, to calculate it:

Kw =[OH⁻] . [H₃O⁺] = x²

x² = 2.4 × 10⁻¹⁴ M²

x = 1.5919 × 10⁻⁷ M

Hence, the concentration of OH and H₃O⁺ (x) = [H₃O⁺] = [OH⁻] = 1.5919×10⁻⁷ M

pH = -log[H₃O⁺] = -log( 1.5919×10⁻⁷ M)

pH = 6.8

Thus, we find that the pH of a neutral aqueous solution at 37 °c (which is the normal human body temperature) is 6.8.

learn more about pH:

brainly.com/question/9529394

#SPJ4

3 0
1 year ago
Consider the following reaction at equilibrium: 2 NH3(g) ⇄ N2(g) + 3 H2(g) What does Le Chatelier's principle predict will happe
BabaBlast [244]

Answer : The equilibrium will shift in the left direction.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The given reaction is:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

As per question, when we are adding N_2  then the concentration of N_2 is increased on product side then the equilibrium will shift in the direction where decrease of concentration of N_2 takes place. Therefore, the equilibrium will shift in the left direction.

Thus, the equilibrium will shift in the left direction.

7 0
3 years ago
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